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Code and Output:
#include <iostream>
using namespace std;
struct Node {
   int data;
   Node* left;
   Node* right;
};
void preorderTraversal(Node* root) {
   if (root == NULL)
      return;
   cout << root->data << " ";
   preorderTraversal(root->left);
   preorderTraversal(root->right);
}
int main() {
   Node* root = new Node();
   root->data = 10;
   root->left = new Node();
   root->left->data = 20;
   root->right = new Node();
   root->right->data = 30;
   preorderTraversal(root);
   return 0;
}
What will be the output of the above code?
  • a)
    10 20 30
  • b)
    20 10 30
  • c)
    10 30 20
  • d)
    20 30 10
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Code and Output:#include <iostream>using namespace std;struct No...
The code defines a binary tree structure using the 'Node' struct, where each node has an integer value ('data') and pointers to its left and right child nodes. In the 'preorderTraversal' function, a recursive pre-order traversal is performed on the tree.
In the 'main' function, a binary tree is constructed with a root node having a value of 10. The left child of the root is assigned a value of 20, and the right child is assigned a value of 30.
The 'preorderTraversal' function is then called with the root node as the argument, which prints the data of the current node, recursively calls 'preorderTraversal' for the left subtree, and then recursively calls 'preorderTraversal' for the right subtree.
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Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer?
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Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer?.
Solutions for Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development. Download more important topics, notes, lectures and mock test series for Software Development Exam by signing up for free.
Here you can find the meaning of Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Code and Output:#include <iostream>using namespace std;struct Node { int data; Node* left; Node* right;};void preorderTraversal(Node* root) { if (root == NULL) return; cout << root->data << " "; preorderTraversal(root->left); preorderTraversal(root->right);}int main() { Node* root = new Node(); root->data = 10; root->left = new Node(); root->left->data = 20; root->right = new Node(); root->right->data = 30; preorderTraversal(root); return 0;}What will be the output of the above code?a)10 20 30b)20 10 30c)10 30 20d)20 30 10Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Software Development tests.
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